1/2y^2-5/2y-18=0

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Solution for 1/2y^2-5/2y-18=0 equation: 


y in (-oo:+oo)

(1/2)*y^2-((5/2)*y)-18 = 0

(1/2)*y^2+(-5/2)*y-18 = 0

1/2*y^2-5/2*y-18 = 0

DELTA = (-5/2)^2-(-18*1/2*4)

DELTA = 169/4

DELTA > 0

y = ((169/4)^(1/2)+5/2)/(1/2*2) or y = (5/2-(169/4)^(1/2))/(1/2*2)

y = 9 or y = -4

y in { -4, 9 }

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